PyQt 中使用 QThread 的后台线程
- 2024-11-29 08:42:00
- admin 原创
- 132
问题描述:
我有一个程序,它通过我在 PyQt 中编写的 GUI 与我正在使用的无线电交互。显然,无线电的主要功能之一是传输数据,但为了连续执行此操作,我必须循环写入,这会导致 GUI 挂起。由于我从未处理过线程,我尝试使用摆脱这些挂起,QCoreApplication.processEvents().
但是无线电需要在传输之间休眠,因此 GUI 仍然会根据这些休眠持续时间挂起。
有没有一种简单的方法可以使用 QThread 来解决这个问题?我查找过有关如何使用 PyQt 实现多线程的教程,但大多数教程都涉及设置服务器,而且比我需要的要高级得多。老实说,我甚至不需要我的线程在运行时更新任何东西,我只需要启动它,让它在后台传输,然后停止它。
解决方案 1:
我创建了一个小示例,展示了处理线程的 3 种不同且简单的方法。我希望它能帮助您找到解决问题的正确方法。
import sys
import time
from PyQt5.QtCore import (QCoreApplication, QObject, QRunnable, QThread,
QThreadPool, pyqtSignal)
# Subclassing QThread
# http://qt-project.org/doc/latest/qthread.html
class AThread(QThread):
def run(self):
count = 0
while count < 5:
time.sleep(1)
print("A Increasing")
count += 1
# Subclassing QObject and using moveToThread
# http://blog.qt.digia.com/blog/2007/07/05/qthreads-no-longer-abstract
class SomeObject(QObject):
finished = pyqtSignal()
def long_running(self):
count = 0
while count < 5:
time.sleep(1)
print("B Increasing")
count += 1
self.finished.emit()
# Using a QRunnable
# http://qt-project.org/doc/latest/qthreadpool.html
# Note that a QRunnable isn't a subclass of QObject and therefore does
# not provide signals and slots.
class Runnable(QRunnable):
def run(self):
count = 0
app = QCoreApplication.instance()
while count < 5:
print("C Increasing")
time.sleep(1)
count += 1
app.quit()
def using_q_thread():
app = QCoreApplication([])
thread = AThread()
thread.finished.connect(app.exit)
thread.start()
sys.exit(app.exec_())
def using_move_to_thread():
app = QCoreApplication([])
objThread = QThread()
obj = SomeObject()
obj.moveToThread(objThread)
obj.finished.connect(objThread.quit)
objThread.started.connect(obj.long_running)
objThread.finished.connect(app.exit)
objThread.start()
sys.exit(app.exec_())
def using_q_runnable():
app = QCoreApplication([])
runnable = Runnable()
QThreadPool.globalInstance().start(runnable)
sys.exit(app.exec_())
if __name__ == "__main__":
#using_q_thread()
#using_move_to_thread()
using_q_runnable()
解决方案 2:
以 PyQt5、python 3.4 更新的答案为例
使用此作为模式来启动一个不获取数据并在数据可用于表单时返回数据的工作者。
1-Worker类变得更小,并放入自己的文件worker.py中,以便于记忆和独立的软件重用。
2 - main.py 文件是定义 GUI 表单类的文件
3-线程对象没有子类化。
4 - 线程对象和工作对象都属于 Form 对象
5-程序步骤在注释中。
# worker.py
from PyQt5.QtCore import QThread, QObject, pyqtSignal, pyqtSlot
import time
class Worker(QObject):
finished = pyqtSignal()
intReady = pyqtSignal(int)
@pyqtSlot()
def procCounter(self): # A slot takes no params
for i in range(1, 100):
time.sleep(1)
self.intReady.emit(i)
self.finished.emit()
主要文件是:
# main.py
from PyQt5.QtCore import QThread
from PyQt5.QtWidgets import QApplication, QLabel, QWidget, QGridLayout
import sys
import worker
class Form(QWidget):
def __init__(self):
super().__init__()
self.label = QLabel("0")
# 1 - create Worker and Thread inside the Form
self.obj = worker.Worker() # no parent!
self.thread = QThread() # no parent!
# 2 - Connect Worker`s Signals to Form method slots to post data.
self.obj.intReady.connect(self.onIntReady)
# 3 - Move the Worker object to the Thread object
self.obj.moveToThread(self.thread)
# 4 - Connect Worker Signals to the Thread slots
self.obj.finished.connect(self.thread.quit)
# 5 - Connect Thread started signal to Worker operational slot method
self.thread.started.connect(self.obj.procCounter)
# * - Thread finished signal will close the app if you want!
#self.thread.finished.connect(app.exit)
# 6 - Start the thread
self.thread.start()
# 7 - Start the form
self.initUI()
def initUI(self):
grid = QGridLayout()
self.setLayout(grid)
grid.addWidget(self.label,0,0)
self.move(300, 150)
self.setWindowTitle('thread test')
self.show()
def onIntReady(self, i):
self.label.setText("{}".format(i))
#print(i)
app = QApplication(sys.argv)
form = Form()
sys.exit(app.exec_())
解决方案 3:
根据 Qt 开发人员的说法,子类化 QThread 是不正确的(请参阅http://blog.qt.io/blog/2010/06/17/youre-doing-it-wrong/)。但那篇文章真的很难理解(而且标题有点居高临下)。我发现了一篇更好的博客文章,它更详细地解释了为什么你应该使用一种线程样式而不是另一种:http://mayaposch.wordpress.com/2011/11/01/how-to-really-truly-use-qthreads-the-full-explanation/
此外,我强烈推荐KDAB 的有关线程间信号和槽的这个视频。
我认为,您可能永远不应该为了重载 run 方法而对线程进行子类化。虽然这样做确实可行,但您基本上是在绕过 Qt 希望您如何工作。此外,您会错过诸如事件和适当的线程安全信号和插槽之类的东西。此外,正如您可能在上面的博客文章中看到的那样,“正确的”线程方式迫使您编写更易于测试的代码。
这里有几个如何在 PyQt 中利用 QThreads 的例子(我在下面发布了一个单独的答案,正确使用了 QRunnable 并结合了信号/槽,如果您有很多需要负载平衡的异步任务,这个答案会更好)。
import sys
from PyQt4 import QtCore
from PyQt4 import QtGui
from PyQt4.QtCore import Qt
# very testable class (hint: you can use mock.Mock for the signals)
class Worker(QtCore.QObject):
finished = QtCore.pyqtSignal()
dataReady = QtCore.pyqtSignal(list, dict)
@QtCore.pyqtSlot()
def processA(self):
print "Worker.processA()"
self.finished.emit()
@QtCore.pyqtSlot(str, list, list)
def processB(self, foo, bar=None, baz=None):
print "Worker.processB()"
for thing in bar:
# lots of processing...
self.dataReady.emit(['dummy', 'data'], {'dummy': ['data']})
self.finished.emit()
class Thread(QtCore.QThread):
"""Need for PyQt4 <= 4.6 only"""
def __init__(self, parent=None):
QtCore.QThread.__init__(self, parent)
# this class is solely needed for these two methods, there
# appears to be a bug in PyQt 4.6 that requires you to
# explicitly call run and start from the subclass in order
# to get the thread to actually start an event loop
def start(self):
QtCore.QThread.start(self)
def run(self):
QtCore.QThread.run(self)
app = QtGui.QApplication(sys.argv)
thread = Thread() # no parent!
obj = Worker() # no parent!
obj.moveToThread(thread)
# if you want the thread to stop after the worker is done
# you can always call thread.start() again later
obj.finished.connect(thread.quit)
# one way to do it is to start processing as soon as the thread starts
# this is okay in some cases... but makes it harder to send data to
# the worker object from the main gui thread. As you can see I'm calling
# processA() which takes no arguments
thread.started.connect(obj.processA)
thread.start()
# another way to do it, which is a bit fancier, allows you to talk back and
# forth with the object in a thread safe way by communicating through signals
# and slots (now that the thread is running I can start calling methods on
# the worker object)
QtCore.QMetaObject.invokeMethod(obj, 'processB', Qt.QueuedConnection,
QtCore.Q_ARG(str, "Hello World!"),
QtCore.Q_ARG(list, ["args", 0, 1]),
QtCore.Q_ARG(list, []))
# that looks a bit scary, but its a totally ok thing to do in Qt,
# we're simply using the system that Signals and Slots are built on top of,
# the QMetaObject, to make it act like we safely emitted a signal for
# the worker thread to pick up when its event loop resumes (so if its doing
# a bunch of work you can call this method 10 times and it will just queue
# up the calls. Note: PyQt > 4.6 will not allow you to pass in a None
# instead of an empty list, it has stricter type checking
app.exec_()
# Without this you may get weird QThread messages in the shell on exit
app.deleteLater()
解决方案 4:
Matt 的例子非常好,我修正了拼写错误,而且 pyqt4.8 现在很常见,所以我删除了虚拟类,并添加了一个 dataReady 信号的示例
# -*- coding: utf-8 -*-
import sys
from PyQt4 import QtCore, QtGui
from PyQt4.QtCore import Qt
# very testable class (hint: you can use mock.Mock for the signals)
class Worker(QtCore.QObject):
finished = QtCore.pyqtSignal()
dataReady = QtCore.pyqtSignal(list, dict)
@QtCore.pyqtSlot()
def processA(self):
print "Worker.processA()"
self.finished.emit()
@QtCore.pyqtSlot(str, list, list)
def processB(self, foo, bar=None, baz=None):
print "Worker.processB()"
for thing in bar:
# lots of processing...
self.dataReady.emit(['dummy', 'data'], {'dummy': ['data']})
self.finished.emit()
def onDataReady(aList, aDict):
print 'onDataReady'
print repr(aList)
print repr(aDict)
app = QtGui.QApplication(sys.argv)
thread = QtCore.QThread() # no parent!
obj = Worker() # no parent!
obj.dataReady.connect(onDataReady)
obj.moveToThread(thread)
# if you want the thread to stop after the worker is done
# you can always call thread.start() again later
obj.finished.connect(thread.quit)
# one way to do it is to start processing as soon as the thread starts
# this is okay in some cases... but makes it harder to send data to
# the worker object from the main gui thread. As you can see I'm calling
# processA() which takes no arguments
thread.started.connect(obj.processA)
thread.finished.connect(app.exit)
thread.start()
# another way to do it, which is a bit fancier, allows you to talk back and
# forth with the object in a thread safe way by communicating through signals
# and slots (now that the thread is running I can start calling methods on
# the worker object)
QtCore.QMetaObject.invokeMethod(obj, 'processB', Qt.QueuedConnection,
QtCore.Q_ARG(str, "Hello World!"),
QtCore.Q_ARG(list, ["args", 0, 1]),
QtCore.Q_ARG(list, []))
# that looks a bit scary, but its a totally ok thing to do in Qt,
# we're simply using the system that Signals and Slots are built on top of,
# the QMetaObject, to make it act like we safely emitted a signal for
# the worker thread to pick up when its event loop resumes (so if its doing
# a bunch of work you can call this method 10 times and it will just queue
# up the calls. Note: PyQt > 4.6 will not allow you to pass in a None
# instead of an empty list, it has stricter type checking
app.exec_()
解决方案 5:
在 PyQt 中,有很多选项可用于获取异步行为。对于需要事件处理的东西(即 QtNetwork 等),您应该使用我在此线程上的其他答案中提供的 QThread 示例。但对于绝大多数线程需求,我认为此解决方案远优于其他方法。
这样做的好处是 QThreadPool 会将您的 QRunnable 实例作为任务进行调度。这类似于英特尔 TBB 中使用的任务模式。它并不像我喜欢的那样优雅,但它确实实现了出色的异步行为。
这样,您就可以通过 QRunnable 在 Python 中充分利用 Qt 的大部分线程功能,同时还能利用信号和槽。我在多个应用程序中使用了相同的代码,有些应用程序会进行数百次异步 REST 调用,有些应用程序会打开文件或列出目录,最好的部分是使用此方法,Qt 任务会为我平衡系统资源。
import time
from PyQt4 import QtCore
from PyQt4 import QtGui
from PyQt4.QtCore import Qt
def async(method, args, uid, readycb, errorcb=None):
"""
Asynchronously runs a task
:param func method: the method to run in a thread
:param object uid: a unique identifier for this task (used for verification)
:param slot updatecb: the callback when data is receieved cb(uid, data)
:param slot errorcb: the callback when there is an error cb(uid, errmsg)
The uid option is useful when the calling code makes multiple async calls
and the callbacks need some context about what was sent to the async method.
For example, if you use this method to thread a long running database call
and the user decides they want to cancel it and start a different one, the
first one may complete before you have a chance to cancel the task. In that
case, the "readycb" will be called with the cancelled task's data. The uid
can be used to differentiate those two calls (ie. using the sql query).
:returns: Request instance
"""
request = Request(method, args, uid, readycb, errorcb)
QtCore.QThreadPool.globalInstance().start(request)
return request
class Request(QtCore.QRunnable):
"""
A Qt object that represents an asynchronous task
:param func method: the method to call
:param list args: list of arguments to pass to method
:param object uid: a unique identifier (used for verification)
:param slot readycb: the callback used when data is receieved
:param slot errorcb: the callback used when there is an error
The uid param is sent to your error and update callbacks as the
first argument. It's there to verify the data you're returning
After created it should be used by invoking:
.. code-block:: python
task = Request(...)
QtCore.QThreadPool.globalInstance().start(task)
"""
INSTANCES = []
FINISHED = []
def __init__(self, method, args, uid, readycb, errorcb=None):
super(Request, self).__init__()
self.setAutoDelete(True)
self.cancelled = False
self.method = method
self.args = args
self.uid = uid
self.dataReady = readycb
self.dataError = errorcb
Request.INSTANCES.append(self)
# release all of the finished tasks
Request.FINISHED = []
def run(self):
"""
Method automatically called by Qt when the runnable is ready to run.
This will run in a separate thread.
"""
# this allows us to "cancel" queued tasks if needed, should be done
# on shutdown to prevent the app from hanging
if self.cancelled:
self.cleanup()
return
# runs in a separate thread, for proper async signal/slot behavior
# the object that emits the signals must be created in this thread.
# Its not possible to run grabber.moveToThread(QThread.currentThread())
# so to get this QObject to properly exhibit asynchronous
# signal and slot behavior it needs to live in the thread that
# we're running in, creating the object from within this thread
# is an easy way to do that.
grabber = Requester()
grabber.Loaded.connect(self.dataReady, Qt.QueuedConnection)
if self.dataError is not None:
grabber.Error.connect(self.dataError, Qt.QueuedConnection)
try:
result = self.method(*self.args)
if self.cancelled:
# cleanup happens in 'finally' statement
return
grabber.Loaded.emit(self.uid, result)
except Exception as error:
if self.cancelled:
# cleanup happens in 'finally' statement
return
grabber.Error.emit(self.uid, unicode(error))
finally:
# this will run even if one of the above return statements
# is executed inside of the try/except statement see:
# https://docs.python.org/2.7/tutorial/errors.html#defining-clean-up-actions
self.cleanup(grabber)
def cleanup(self, grabber=None):
# remove references to any object or method for proper ref counting
self.method = None
self.args = None
self.uid = None
self.dataReady = None
self.dataError = None
if grabber is not None:
grabber.deleteLater()
# make sure this python obj gets cleaned up
self.remove()
def remove(self):
try:
Request.INSTANCES.remove(self)
# when the next request is created, it will clean this one up
# this will help us avoid this object being cleaned up
# when it's still being used
Request.FINISHED.append(self)
except ValueError:
# there might be a race condition on shutdown, when shutdown()
# is called while the thread is still running and the instance
# has already been removed from the list
return
@staticmethod
def shutdown():
for inst in Request.INSTANCES:
inst.cancelled = True
Request.INSTANCES = []
Request.FINISHED = []
class Requester(QtCore.QObject):
"""
A simple object designed to be used in a separate thread to allow
for asynchronous data fetching
"""
#
# Signals
#
Error = QtCore.pyqtSignal(object, unicode)
"""
Emitted if the fetch fails for any reason
:param unicode uid: an id to identify this request
:param unicode error: the error message
"""
Loaded = QtCore.pyqtSignal(object, object)
"""
Emitted whenever data comes back successfully
:param unicode uid: an id to identify this request
:param list data: the json list returned from the GET
"""
NetworkConnectionError = QtCore.pyqtSignal(unicode)
"""
Emitted when the task fails due to a network connection error
:param unicode message: network connection error message
"""
def __init__(self, parent=None):
super(Requester, self).__init__(parent)
class ExampleObject(QtCore.QObject):
def __init__(self, parent=None):
super(ExampleObject, self).__init__(parent)
self.uid = 0
self.request = None
def ready_callback(self, uid, result):
if uid != self.uid:
return
print "Data ready from %s: %s" % (uid, result)
def error_callback(self, uid, error):
if uid != self.uid:
return
print "Data error from %s: %s" % (uid, error)
def fetch(self):
if self.request is not None:
# cancel any pending requests
self.request.cancelled = True
self.request = None
self.uid += 1
self.request = async(slow_method, ["arg1", "arg2"], self.uid,
self.ready_callback,
self.error_callback)
def slow_method(arg1, arg2):
print "Starting slow method"
time.sleep(1)
return arg1 + arg2
if __name__ == "__main__":
import sys
app = QtGui.QApplication(sys.argv)
obj = ExampleObject()
dialog = QtGui.QDialog()
layout = QtGui.QVBoxLayout(dialog)
button = QtGui.QPushButton("Generate", dialog)
progress = QtGui.QProgressBar(dialog)
progress.setRange(0, 0)
layout.addWidget(button)
layout.addWidget(progress)
button.clicked.connect(obj.fetch)
dialog.show()
app.exec_()
app.deleteLater() # avoids some QThread messages in the shell on exit
# cancel all running tasks avoid QThread/QTimer error messages
# on exit
Request.shutdown()
退出应用程序时,您需要确保取消所有任务,否则应用程序将挂起,直到每个计划的任务都完成
解决方案 6:
根据其他答案中提到的 Worker 对象方法,我决定看看是否可以扩展解决方案以调用更多线程 - 在这种情况下,机器可以运行的最佳数量,并启动具有不确定完成时间的多个工作器。为此,我仍然需要子类化 QThread - 但只需分配一个线程号并“重新实现”信号“完成”和“启动”以包含它们的线程号。
我非常关注主 GUI、线程和工作程序之间的信号。
同样,其他答案也费尽心思指出不将 QThread 作为父级,但我不认为这是一个真正的问题。但是,我的代码也小心地销毁了 QThread 对象。
但是,我无法为工作对象指定父级,因此似乎最好向它们发送 deleteLater() 信号,无论是在线程函数完成时还是在 GUI 被销毁时。我自己的代码就因为没有这样做而挂起。
我认为另一个必要的改进是重新实现 GUI (QWidget) 的 closeEvent,这样线程将被指示退出,然后 GUI 将等待直到所有线程完成。当我玩这个问题的其他一些答案时,我得到了 QThread 被破坏的错误。
也许这对其他人有用。我确实发现这是一个有用的练习。也许其他人会知道线程宣布其身份的更好方法。
#!/usr/bin/env python3
#coding:utf-8
# Author: --<>
# Purpose: To demonstrate creation of multiple threads and identify the receipt of thread results
# Created: 19/12/15
import sys
from PyQt4.QtCore import QThread, pyqtSlot, pyqtSignal
from PyQt4.QtGui import QApplication, QLabel, QWidget, QGridLayout
import sys
import worker
class Thread(QThread):
#make new signals to be able to return an id for the thread
startedx = pyqtSignal(int)
finishedx = pyqtSignal(int)
def __init__(self,i,parent=None):
super().__init__(parent)
self.idd = i
self.started.connect(self.starttt)
self.finished.connect(self.finisheddd)
@pyqtSlot()
def starttt(self):
print('started signal from thread emitted')
self.startedx.emit(self.idd)
@pyqtSlot()
def finisheddd(self):
print('finished signal from thread emitted')
self.finishedx.emit(self.idd)
class Form(QWidget):
def __init__(self):
super().__init__()
self.initUI()
self.worker={}
self.threadx={}
self.i=0
i=0
#Establish the maximum number of threads the machine can optimally handle
#Generally relates to the number of processors
self.threadtest = QThread(self)
self.idealthreadcount = self.threadtest.idealThreadCount()
print("This machine can handle {} threads optimally".format(self.idealthreadcount))
while i <self.idealthreadcount:
self.setupThread(i)
i+=1
i=0
while i<self.idealthreadcount:
self.startThread(i)
i+=1
print("Main Gui running in thread {}.".format(self.thread()))
def setupThread(self,i):
self.worker[i]= worker.Worker(i) # no parent!
#print("Worker object runningt in thread {} prior to movetothread".format(self.worker[i].thread()) )
self.threadx[i] = Thread(i,parent=self) # if parent isn't specified then need to be careful to destroy thread
self.threadx[i].setObjectName("python thread{}"+str(i))
#print("Thread object runningt in thread {} prior to movetothread".format(self.threadx[i].thread()) )
self.threadx[i].startedx.connect(self.threadStarted)
self.threadx[i].finishedx.connect(self.threadFinished)
self.worker[i].finished.connect(self.workerFinished)
self.worker[i].intReady.connect(self.workerResultReady)
#The next line is optional, you may want to start the threads again without having to create all the code again.
self.worker[i].finished.connect(self.threadx[i].quit)
self.threadx[i].started.connect(self.worker[i].procCounter)
self.destroyed.connect(self.threadx[i].deleteLater)
self.destroyed.connect(self.worker[i].deleteLater)
#This is the key code that actually get the worker code onto another processor or thread.
self.worker[i].moveToThread(self.threadx[i])
def startThread(self,i):
self.threadx[i].start()
@pyqtSlot(int)
def threadStarted(self,i):
print('Thread {} started'.format(i))
print("Thread priority is {}".format(self.threadx[i].priority()))
@pyqtSlot(int)
def threadFinished(self,i):
print('Thread {} finished'.format(i))
@pyqtSlot(int)
def threadTerminated(self,i):
print("Thread {} terminated".format(i))
@pyqtSlot(int,int)
def workerResultReady(self,j,i):
print('Worker {} result returned'.format(i))
if i ==0:
self.label1.setText("{}".format(j))
if i ==1:
self.label2.setText("{}".format(j))
if i ==2:
self.label3.setText("{}".format(j))
if i ==3:
self.label4.setText("{}".format(j))
#print('Thread {} has started'.format(self.threadx[i].currentThreadId()))
@pyqtSlot(int)
def workerFinished(self,i):
print('Worker {} finished'.format(i))
def initUI(self):
self.label1 = QLabel("0")
self.label2= QLabel("0")
self.label3= QLabel("0")
self.label4 = QLabel("0")
grid = QGridLayout(self)
self.setLayout(grid)
grid.addWidget(self.label1,0,0)
grid.addWidget(self.label2,0,1)
grid.addWidget(self.label3,0,2)
grid.addWidget(self.label4,0,3) #Layout parents the self.labels
self.move(300, 150)
self.setGeometry(0,0,300,300)
#self.size(300,300)
self.setWindowTitle('thread test')
self.show()
def closeEvent(self, event):
print('Closing')
#this tells the threads to stop running
i=0
while i <self.idealthreadcount:
self.threadx[i].quit()
i+=1
#this ensures window cannot be closed until the threads have finished.
i=0
while i <self.idealthreadcount:
self.threadx[i].wait()
i+=1
event.accept()
if __name__=='__main__':
app = QApplication(sys.argv)
form = Form()
sys.exit(app.exec_())
下面是工人代码
#!/usr/bin/env python3
#coding:utf-8
# Author: --<>
# Purpose: Stack Overflow
# Created: 19/12/15
import sys
import unittest
from PyQt4.QtCore import QThread, QObject, pyqtSignal, pyqtSlot
import time
import random
class Worker(QObject):
finished = pyqtSignal(int)
intReady = pyqtSignal(int,int)
def __init__(self, i=0):
'''__init__ is called while the worker is still in the Gui thread. Do not put slow or CPU intensive code in the __init__ method'''
super().__init__()
self.idd = i
@pyqtSlot()
def procCounter(self): # This slot takes no params
for j in range(1, 10):
random_time = random.weibullvariate(1,2)
time.sleep(random_time)
self.intReady.emit(j,self.idd)
print('Worker {0} in thread {1}'.format(self.idd, self.thread().idd))
self.finished.emit(self.idd)
if __name__=='__main__':
unittest.main()
解决方案 7:
PySide2解决方案:
与 PyQt5 不同,在 PySide2 中,QThread.started 信号是在原始线程而不是工作线程上接收/处理的!幸运的是,它仍然在工作线程上接收所有其他信号。
为了匹配 PyQt5 的行为,您必须自己创建已启动信号。
这是一个简单的解决方案:
# Use this class instead of QThread
class QThread2(QThread):
# Use this signal instead of "started"
started2 = Signal()
def __init__(self):
QThread.__init__(self)
self.started.connect(self.onStarted)
def onStarted(self):
self.started2.emit()
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