使用 Python 发送 HTML 电子邮件
- 2024-12-17 08:30:00
- admin 原创
- 147
问题描述:
如何使用 Python 在电子邮件中发送 HTML 内容?我可以发送简单的文本。
解决方案 1:
来自Python v2.7.14 文档 - 18.1.11。电子邮件:示例:
以下是如何创建具有备用纯文本版本的 HTML 消息的示例:
#! /usr/bin/python
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
# me == my email address
# you == recipient's email address
me = "my@email.com"
you = "your@email.com"
# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = "Link"
msg['From'] = me
msg['To'] = you
# Create the body of the message (a plain-text and an HTML version).
text = "Hi!
How are you?
Here is the link you wanted:
http://www.python.org"
html = """\n<html>
<head></head>
<body>
<p>Hi!<br>
How are you?<br>
Here is the <a href="http://www.python.org">link</a> you wanted.
</p>
</body>
</html>
"""
# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)
# Send the message via local SMTP server.
s = smtplib.SMTP('localhost')
# sendmail function takes 3 arguments: sender's address, recipient's address
# and message to send - here it is sent as one string.
s.sendmail(me, you, msg.as_string())
s.quit()
解决方案 2:
以下是Gmail对已接受答案的实现:
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
# me == my email address
# you == recipient's email address
me = "my@email.com"
you = "your@email.com"
# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = "Link"
msg['From'] = me
msg['To'] = you
# Create the body of the message (a plain-text and an HTML version).
text = "Hi!
How are you?
Here is the link you wanted:
http://www.python.org"
html = """\n<html>
<head></head>
<body>
<p>Hi!<br>
How are you?<br>
Here is the <a href="http://www.python.org">link</a> you wanted.
</p>
</body>
</html>
"""
# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)
# Send the message via local SMTP server.
mail = smtplib.SMTP('smtp.gmail.com', 587)
mail.ehlo()
mail.starttls()
mail.login('userName', 'password')
mail.sendmail(me, you, msg.as_string())
mail.quit()
解决方案 3:
您可以尝试使用我的邮件模块。
from mailer import Mailer
from mailer import Message
message = Message(From="me@example.com",
To="you@example.com")
message.Subject = "An HTML Email"
message.Html = """<p>Hi!<br>
How are you?<br>
Here is the <a href="http://www.python.org">link</a> you wanted.</p>"""
sender = Mailer('smtp.example.com')
sender.send(message)
解决方案 4:
这是一个发送 HTML 电子邮件的简单方法,只需将 Content-Type 标头指定为“text/html”:
import email.message
import smtplib
msg = email.message.Message()
msg['Subject'] = 'foo'
msg['From'] = 'sender@test.com'
msg['To'] = 'recipient@test.com'
msg.add_header('Content-Type','text/html')
msg.set_payload('Body of <b>message</b>')
# Send the message via local SMTP server.
s = smtplib.SMTP('localhost')
s.starttls()
s.login(email_login,
email_passwd)
s.sendmail(msg['From'], [msg['To']], msg.as_string())
s.quit()
解决方案 5:
对于 python3,改进@taltman 的答案:
使用
email.message.EmailMessage
而不是email.message.Message
来构建电子邮件。使用
email.set_content
func,分配subtype='html'
参数。而不是低级函数set_payload
并手动添加标题。使用
SMTP.send_message
func 而不是SMTP.sendmail
func 来发送电子邮件。使用
with
块自动关闭连接。
from email.message import EmailMessage
from smtplib import SMTP
# construct email
email = EmailMessage()
email['Subject'] = 'foo'
email['From'] = 'sender@test.com'
email['To'] = 'recipient@test.com'
email.set_content('<font color="red">red color text</font>', subtype='html')
# Send the message via local SMTP server.
with SMTP('localhost') as s:
s.login('foo_user', 'bar_password')
s.send_message(email)
解决方案 6:
这是示例代码。这是从Python Cookbook网站上的代码中得到的启发(找不到确切的链接)
def createhtmlmail (html, text, subject, fromEmail):
"""Create a mime-message that will render HTML in popular
MUAs, text in better ones"""
import MimeWriter
import mimetools
import cStringIO
out = cStringIO.StringIO() # output buffer for our message
htmlin = cStringIO.StringIO(html)
txtin = cStringIO.StringIO(text)
writer = MimeWriter.MimeWriter(out)
#
# set up some basic headers... we put subject here
# because smtplib.sendmail expects it to be in the
# message body
#
writer.addheader("From", fromEmail)
writer.addheader("Subject", subject)
writer.addheader("MIME-Version", "1.0")
#
# start the multipart section of the message
# multipart/alternative seems to work better
# on some MUAs than multipart/mixed
#
writer.startmultipartbody("alternative")
writer.flushheaders()
#
# the plain text section
#
subpart = writer.nextpart()
subpart.addheader("Content-Transfer-Encoding", "quoted-printable")
pout = subpart.startbody("text/plain", [("charset", 'us-ascii')])
mimetools.encode(txtin, pout, 'quoted-printable')
txtin.close()
#
# start the html subpart of the message
#
subpart = writer.nextpart()
subpart.addheader("Content-Transfer-Encoding", "quoted-printable")
#
# returns us a file-ish object we can write to
#
pout = subpart.startbody("text/html", [("charset", 'us-ascii')])
mimetools.encode(htmlin, pout, 'quoted-printable')
htmlin.close()
#
# Now that we're done, close our writer and
# return the message body
#
writer.lastpart()
msg = out.getvalue()
out.close()
print msg
return msg
if __name__=="__main__":
import smtplib
html = 'html version'
text = 'TEST VERSION'
subject = "BACKUP REPORT"
message = createhtmlmail(html, text, subject, 'From Host <sender@host.com>')
server = smtplib.SMTP("smtp_server_address","smtp_port")
server.login('username', 'password')
server.sendmail('sender@host.com', 'target@otherhost.com', message)
server.quit()
解决方案 7:
实际上,yagmail采取了稍微不同的方法。
默认情况下,它会发送 HTML,并针对无法阅读电子邮件的用户自动回退。这已经不是 17 世纪了。
当然,它可以被覆盖,但是这里是:
import yagmail
yag = yagmail.SMTP("me@example.com", "mypassword")
html_msg = """<p>Hi!<br>
How are you?<br>
Here is the <a href="http://www.python.org">link</a> you wanted.</p>"""
yag.send("to@example.com", "the subject", html_msg)
有关安装说明和更多强大功能,请查看github。
解决方案 8:
smtplib
这是一个使用 CC 和 BCC 选项从 Python 发送纯文本和 HTML 电子邮件的工作示例。
https://varunver.wordpress.com/2017/01/26/python-smtplib-send-plaintext-and-html-emails/
#!/usr/bin/env python
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
def send_mail(params, type_):
email_subject = params['email_subject']
email_from = "from_email@domain.com"
email_to = params['email_to']
email_cc = params.get('email_cc')
email_bcc = params.get('email_bcc')
email_body = params['email_body']
msg = MIMEMultipart('alternative')
msg['To'] = email_to
msg['CC'] = email_cc
msg['Subject'] = email_subject
mt_html = MIMEText(email_body, type_)
msg.attach(mt_html)
server = smtplib.SMTP('YOUR_MAIL_SERVER.DOMAIN.COM')
server.set_debuglevel(1)
toaddrs = [email_to] + [email_cc] + [email_bcc]
server.sendmail(email_from, toaddrs, msg.as_string())
server.quit()
# Calling the mailer functions
params = {
'email_to': 'to_email@domain.com',
'email_cc': 'cc_email@domain.com',
'email_bcc': 'bcc_email@domain.com',
'email_subject': 'Test message from python library',
'email_body': '<h1>Hello World</h1>'
}
for t in ['plain', 'html']:
send_mail(params, t)
解决方案 9:
如果你想要更简单的东西:
from redmail import EmailSender
email = EmailSender(host="smtp.myhost.com", port=1)
email.send(
subject="Example email",
sender="me@example.com",
receivers=["you@example.com"],
html="<h1>Hi, this is HTML body</h1>"
)
Pip 从PyPI安装 Red Mail :
pip install redmail
Red Mail 很可能满足您发送电子邮件的所有需求,它具有许多功能,包括:
附件
模板(使用 Jinja)
嵌入图像
美化表格
以抄送或密送形式发送
Gmail 预配置
文档:https://red-mail.readthedocs.io/en/latest/index.html
源代码:https://github.com/Miksus/red-mail
解决方案 10:
我可能在这里回答得晚了,但问题询问了发送 HTML 电子邮件的方法。使用像“电子邮件”这样的专用模块是可以的,但我们可以在不使用任何新模块的情况下实现相同的结果。这一切都归结为 Gmail 协议。
下面是我仅使用“smtplib”发送 HTML 邮件的简单示例代码。此代码仅适用于发送简单且较小的 HTML 内容。
import smtplib
FROM = "....@gmail.com"
TO = "another....@gmail.com"
SUBJECT= "Subject"
PWD = "thesecretkey"
TEXT="""
<h1>Hello</h1>
""" #Your Message (Even Supports HTML Directly)
message = f"Subject: {SUBJECT}
From: {FROM}
To: {TO}
Content-Type: text/html
{TEXT}" #This is where the stuff happens
try:
server=smtplib.SMTP("smtp.gmail.com",587)
server.ehlo()
server.starttls()
server.login(FROM,PWD)
server.sendmail(FROM,TO,message)
server.close()
print("Successfully sent the mail.")
except Exception as e:
print("Failed to send the mail..", e)
解决方案 11:
这是我对使用 boto3 的 AWS 的回答
subject = "Hello"
html = "<b>Hello Consumer</b>"
client = boto3.client('ses', region_name='us-east-1', aws_access_key_id="your_key",
aws_secret_access_key="your_secret")
client.send_email(
Source='ACME <do-not-reply@acme.com>',
Destination={'ToAddresses': [email]},
Message={
'Subject': {'Data': subject},
'Body': {
'Html': {'Data': html}
}
}
解决方案 12:
从 Office 365 中的组织帐户发送电子邮件的最简单解决方案:
from O365 import Message
html_template = """
<html>
<head>
<title></title>
</head>
<body>
{}
</body>
</html>
"""
final_html_data = html_template.format(df.to_html(index=False))
o365_auth = ('sender_username@company_email.com','Password')
m = Message(auth=o365_auth)
m.setRecipients('receiver_username@company_email.com')
m.setSubject('Weekly report')
m.setBodyHTML(final_html_data)
m.sendMessage()
这里df是一个转换为 html 表的数据框,它被注入到 html_template