我如何构建多个提交按钮的 django 表单？

问题描述：

我有一个表格，其中包含一个电子邮件输入和两个用于订阅和取消订阅新闻通讯的提交按钮：

<form action="" method="post">
{{ form_newsletter }}
<input type="submit" name="newsletter_sub" value="Subscribe" />
<input type="submit" name="newsletter_unsub" value="Unsubscribe" />
</form>

我也有上课形式：

class NewsletterForm(forms.ModelForm):
    class Meta:
        model = Newsletter
        fields = ('email',)

我必须编写自己的 clean_email 方法，并且需要知道通过哪个按钮提交了表单。但是提交按钮的值不在self.cleaned_data字典中。我可以用其他方式获取按钮的值吗？

解决方案 1：

例如：

if 'newsletter_sub' in request.POST:
    # do subscribe
elif 'newsletter_unsub' in request.POST:
    # do unsubscribe

解决方案 2：

您可以在验证之前使用self.data该clean_email方法访问 POST 数据。它应该包含一个名为newsletter_sub或的键，newsletter_unsub具体取决于按下了哪个按钮。

# in the context of a django.forms form

def clean(self):
    if 'newsletter_sub' in self.data:
        # do subscribe
    elif 'newsletter_unsub' in self.data:
        # do unsubscribe

解决方案 3：

你也可以这样做，

 <form method='POST'>
    {{form1.as_p}}
    <button type="submit" name="btnform1">Save Changes</button>
    </form>
    <form method='POST'>
    {{form2.as_p}}
    <button type="submit" name="btnform2">Save Changes</button>
    </form>

代码

if request.method=='POST' and 'btnform1' in request.POST:
    do something...
if request.method=='POST' and 'btnform2' in request.POST:
    do something...

解决方案 4：

一个 URL 指向同一个视图！就像这样！

urls.py

url(r'^$', views.landing.as_view(), name = 'landing'),

视图.py

class landing(View):
        template_name = '/home.html'
        form_class1 = forms.pynamehere1
        form_class2 = forms.pynamehere2
            def get(self, request):
                form1 = self.form_class1(None)
                form2 = self.form_class2(None)
                return render(request, self.template_name, { 'register':form1, 'login':form2,})

             def post(self, request):
                 if request.method=='POST' and 'htmlsubmitbutton1' in request.POST:
                        ## do what ever you want to do for first function ####
                 if request.method=='POST' and 'htmlsubmitbutton2' in request.POST:
                         ## do what ever you want to do for second function ####
                        ## return def post###  
                 return render(request, self.template_name, {'form':form,})

/home.html
    <!-- #### form 1 #### -->
    <form action="" method="POST" >
      {% csrf_token %}
      {{ register.as_p }}
    <button type="submit" name="htmlsubmitbutton1">Login</button>
    </form>
    <!--#### form 2 #### -->
    <form action="" method="POST" >
      {% csrf_token %}
      {{ login.as_p }}
    <button type="submit" name="htmlsubmitbutton2">Login</button>
    </form>

解决方案 5：

这是一个老问题，尽管如此，我还是遇到了同样的问题并找到了一个适合我的解决方案：我编写了 MultiRedirectMixin。

from django.http import HttpResponseRedirect

class MultiRedirectMixin(object):
    """
    A mixin that supports submit-specific success redirection.
     Either specify one success_url, or provide dict with names of 
     submit actions given in template as keys
     Example: 
       In template:
         <input type="submit" name="create_new" value="Create"/>
         <input type="submit" name="delete" value="Delete"/>
       View:
         MyMultiSubmitView(MultiRedirectMixin, forms.FormView):
             success_urls = {"create_new": reverse_lazy('create'),
                               "delete": reverse_lazy('delete')}
    """
    success_urls = {}  

    def form_valid(self, form):
        """ Form is valid: Pick the url and redirect.
        """

        for name in self.success_urls:
            if name in form.data:
                self.success_url = self.success_urls[name]
                break

        return HttpResponseRedirect(self.get_success_url())

    def get_success_url(self):
        """
        Returns the supplied success URL.
        """
        if self.success_url:
            # Forcing possible reverse_lazy evaluation
            url = force_text(self.success_url)
        else:
            raise ImproperlyConfigured(
                _("No URL to redirect to. Provide a success_url."))
        return url

解决方案 6：

我知道这已经很老了，但有些答案至少可以说是简短的，而且它们没有解决表单不是 django 表单的常见情况。

这个解决方案的灵感来自这篇博客文章。它依赖于使用从 django.views.generic.edit.FormMixin 派生的视图类，例如 CreateView、UpdateView 或 DeleteView。它们提供了get_success_url方法，该方法在请求中公开按钮名称

html

<html>
    <body>
        <form method="post">
            <div>
                <label> <input type="radio" name="select-type" value="A">Type A</label>
            </div>
            <div>
                <label> <input type="radio" name="select-type" value="B">Type B</label>
            </div>
            <div>
                <input type="submit" value="Use selected">
            </div>
            <div>
                <input type="submit" name="no-selection" value="None of the above">
            </div>
        </form>
    </body>
</html>

视图.py

from django.views.generic import UpdateView

class GetType(UpdateView):
    def get(self, request):
        return render(request, 'get_type.html', {})

    def post(self, request):
        button = self.get_success_url()
        print(button)

    def get_success_url(self):
        if 'no-selection' in self.request.POST:
            return 'none selected'
        return ''